3x^(2/3)-7x^(1/3)-6=0

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Solution for 3x^(2/3)-7x^(1/3)-6=0 equation: 


x in (-oo:+oo)

3*x^(2/3)-(7*x^(1/3))-6 = 0

3*x^(2/3)-7*x^(1/3)-6 = 0

t_1 = x^(1/3)

3*t_1^2-7*t_1^1-6 = 0

3*t_1^2-7*t_1-6 = 0

DELTA = (-7)^2-(-6*3*4)

DELTA = 121

DELTA > 0

t_1 = (121^(1/2)+7)/(2*3) or t_1 = (7-121^(1/2))/(2*3)

t_1 = 3 or t_1 = -2/3

t_1 = -2/3

x^(1/3)+2/3 = 0

1*x^(1/3) = -2/3 // : 1

x^(1/3) = -2/3

( -2/3 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 3

x^(1/3)-3 = 0

1*x^(1/3) = 3 // : 1

x^(1/3) = 3

x^(1/3) = 3 // ^ 3

x = 27

x = 27

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